比较函数返回值错误

Incorrect Return Value for Comparison Function?

本文关键字:错误 返回值 函数 比较      更新时间:2023-09-26

函数expensiveItem(menu)应该返回数组中最贵的项,即饭菜。在本例中,它应该返回"Double Quarter Pounder with Cheese"。相反,它返回"Double Cheeseburger"。我的代码哪里出错了?

var item1 = {
  name: "Big Mac",
  price: 3.99,
  calories: 530
};
var item2 = {
  name: "Filet-O-Fish",
  price: 3.79,
  calories: 390
};
var item3 = {
  name: "Double Cheeseburger",
  price: 1.59,
  calories: 430
};
var item4 = {
  name: "Double Quarter Pounder with Cheese",
  price: 4.79,
  calories: 740
};
var item5 = {
  name: "Chicken McNuggets",
  price: 4.49,
  calories: 190
};
var meals = [item1, item2, item3, item4, item5];
function init() {
  var lowestCost = document.getElementById('cheapestItem');
  lowestCost.onclick = function() {
    cheapestItem(meals);
  }
  var highestCost = document.getElementById('highestCost');
  highestCost.onclick = function() {
    expensiveItem(meals);
  }
}
window.onload = init;
// return name of cheapest item on menu
function cheapestItem(menu) {
  var msg = document.getElementById('msg1'); // is this necessary? Code works fine without it...
  var cheapestItem = operation(menu, "less");
  msg1.innerHTML = "The cheapest item is " + cheapestItem;
}
// return name of most expensive item on menu
function expensiveItem(menu) {
  var msg = document.getElementById('msg2');
  var expensiveItem = operation(menu, "greater");
  msg2.innerHTML = "The most expensive item is " + expensiveItem;
}
//return result based on given comparator operator
function operation(menu, op) {
  var v1 = menu[0].price;
  var item;
  for (var i = 0; i < menu.length; i++) {
    var v2 = menu[i].price;
    if ((op == "less" && (v2 < v1)) ||
      (op == "greater" && (v2 > v1))) {
      result = v2;
      item = menu[i].name;
    }
  }
  console.log(item);
  return item;
}
<body>
  <input type="button" id="cheapestItem" value="Cheapest Item">
  </div>
  <p id="msg1">message 1</p>
  <input type="button" id="highestCost" value="Most Expensive Item">
  </div>
  <p id="msg2">message 2</p>
</body>

问题就在这里:

if ((op == "less" && (v2 < v1)) || (op == "greater" && (v2 > v1)))

您只比较v1v2,但如果条件满足,您也应该分配v2v1值。

解释:

以下是循环

中的值
3.99 3.99
3.99 3.79
3.99 1.59
3.99 4.79
4.79 4.49

如果您注意到,最后2个操作满足条件。所以你会得到后者。

var item1 = {
  name: "Big Mac",
  price: 3.99,
  calories: 530
};
var item2 = {
  name: "Filet-O-Fish",
  price: 3.79,
  calories: 390
};
var item3 = {
  name: "Double Cheeseburger",
  price: 1.59,
  calories: 430
};
var item4 = {
  name: "Double Quarter Pounder with Cheese",
  price: 4.79,
  calories: 740
};
var item5 = {
  name: "Chicken McNuggets",
  price: 4.49,
  calories: 190
};
var meals = [item1, item2, item3, item4, item5];

function init() {
  var lowestCost = document.getElementById('cheapestItem');
  lowestCost.onclick = function() {
    cheapestItem(meals);
  }
  var highestCost = document.getElementById('highestCost');
  highestCost.onclick = function() {
    expensiveItem(meals);
  }
}
window.onload = init;

// return name of cheapest item on menu
function cheapestItem(menu) {
  var msg = document.getElementById('msg1'); // is this necessary? Code works fine without it...
  var cheapestItem = operation(menu, "less");
  msg1.innerHTML = "The cheapest item is " + cheapestItem;
}
// return name of most expensive item on menu
function expensiveItem(menu) {
  var msg = document.getElementById('msg2');
  var expensiveItem = operation(menu, "greater");
  msg2.innerHTML = "The most expensive item is " + expensiveItem;
}
//return result based on given comparator operator
function operation(menu, op) {
  var v1 = menu[0].price;
  var item;
  for (var i = 0; i < menu.length; i++) {
    var v2 = menu[i].price;
    if ((op == "less" && (v2 <= v1)) ||
      (op == "greater" && (v2 >= v1))) {
      result = v1 = v2;
      item = menu[i].name;
    }
  }
  console.log(item);
  return item;
}
<body>
  <input type="button" id="cheapestItem" value="Cheapest Item">
  </div>
  <p id="msg1">message 1</p>
  <input type="button" id="highestCost" value="Most Expensive Item">
  </div>
  <p id="msg2">message 2</p>
</body>

<

交替方式/h3>

init中排序你的数组。现在你不需要循环获取最小值和最大值。

注意:使用window.load = function是不好的做法,你应该使用window.addEventListener('load', function)来代替

var item1 = {
  name: "Big Mac",
  price: 3.99,
  calories: 530
};
var item2 = {
  name: "Filet-O-Fish",
  price: 3.79,
  calories: 390
};
var item3 = {
  name: "Double Cheeseburger",
  price: 1.59,
  calories: 430
};
var item4 = {
  name: "Double Quarter Pounder with Cheese",
  price: 4.79,
  calories: 740
};
var item5 = {
  name: "Chicken McNuggets",
  price: 4.49,
  calories: 190
};
var meals = [item1, item2, item3, item4, item5];
var OP_LESS = "less";
var OP_GREATER = "greater";
function init() {
  var lowestCost = document.getElementById('cheapestItem');
  lowestCost.onclick = function() {
    cheapestItem(meals);
  }
  var highestCost = document.getElementById('highestCost');
  highestCost.onclick = function() {
    expensiveItem(meals);
  }
  sortData();
}
function sortData(){
  meals.sort(function(a,b){
    return a.price > b.price ? 1 : a.price < b.price ? -1 : 0
  });
}
window.addEventListener('load', init);
// return name of cheapest item on menu
function cheapestItem(menu) {
  var msg = document.getElementById('msg1'); // is this necessary? Code works fine without it...
  var cheapestItem = operation(menu, OP_LESS);
  msg1.innerHTML = "The cheapest item is " + cheapestItem;
}
// return name of most expensive item on menu
function expensiveItem(menu) {
  var msg = document.getElementById('msg2');
  var expensiveItem = operation(menu, OP_GREATER);
  msg2.innerHTML = "The most expensive item is " + expensiveItem;
}
//return result based on given comparator operator
function operation(menu, op) {
  return (op === OP_LESS ? meals[0] : meals[meals.length-1]).name
}
<body>
  <input type="button" id="cheapestItem" value="Cheapest Item">
  </div>
  <p id="msg1">message 1</p>
  <input type="button" id="highestCost" value="Most Expensive Item">
  </div>
  <p id="msg2">message 2</p>
</body>

您总是与初始v1值进行比较,当您发现"较大"时,您应该将新值设置为var v1。

if ((op == "less" && (v2 < v1)) ||
    (op == "greater" && (v2 > v1))) {
    result = v2;
    v1=v2; //Set new greater/lower value
    item = menu[i].name;
}

我建议只使用一个变量来测试并返回

function operation(menu, op) {
    var price = menu[0].price,
        item = menu[0].name;
    for (var i = 0; i < menu.length; i++) {
        if (
            op === "less"    && menu[i].price < price ||
            op === "greater" && menu[i].price > price
        ) {
            price = menu[i].price;
            item = menu[i].name;
        }
    }
    console.log(item);
    return item;
}

var item1 = {      name: "Big Mac",      price: 3.99,      calories: 530    };
var item2 = {      name: "Filet-O-Fish",      price: 3.79,      calories: 390    };
var item3 = {      name: "Double Cheeseburger",      price: 1.59,      calories: 430    };
var item4 = {      name: "Double Quarter Pounder with Cheese",      price: 4.79,      calories: 740
};
var item5 = {      name: "Chicken McNuggets",      price: 4.49,      calories: 190    };
var meals = [item1, item2, item3, item4, item5];
function init() {
  var lowestCost = document.getElementById('cheapestItem');
  lowestCost.onclick = function() {
    cheapestItem(meals);
  }
  var highestCost = document.getElementById('highestCost');
  highestCost.onclick = function() {
    expensiveItem(meals);
  }
}
window.onload = init;
// return name of cheapest item on menu
function cheapestItem(menu) {
  var msg = document.getElementById('msg1'); // is this necessary? Code works fine without it...
  var cheapestItem = operation(menu, "less");
  msg1.innerHTML = "The cheapest item is " + cheapestItem;
}
// return name of most expensive item on menu
function expensiveItem(menu) {
  var msg = document.getElementById('msg2');
  var expensiveItem = operation(menu, "greater");
  msg2.innerHTML = "The most expensive item is " + expensiveItem;
}
//return result based on given comparator operator
function operation(menu, op) {
  var price = menu[0].price,
      item = menu[0].name;
  for (var i = 0; i < menu.length; i++) {
    if (op == "less" && menu[i].price < price || op == "greater" && menu[i].price > price) {
      price = menu[i].price;
      item = menu[i].name;
    }
  }
  console.log(item);
  return item;
}
  <input type="button" id="cheapestItem" value="Cheapest Item">
  <p id="msg1">message 1</p>
  <input type="button" id="highestCost" value="Most Expensive Item">
  <p id="msg2">message 2</p>