为什么我的方法没有返回对象

我的ajax响应是正确的，但我无法将响应对象返回给我的方法调用。问题出在if语句的第一部分。这是我第一个尝试面向对象的项目。请让我知道如何解决这个问题和任何其他OOP代码的建议是非常欢迎的。

$("#search-btn").on('click', function(e) {
        e.preventDefault();
        searchTerm = $("#search-input").val();
        var params = {'q': searchTerm, 'limit': 13};
        var url = "https://api.twitch.tv/kraken/search/" + searchType + "?";
/*===*/     if(searchType === "games") {
            url = "https://api.twitch.tv/kraken/search/games?type=suggest";
            var gamesSearch = new TwitchApiCall(searchType, searchTerm, params, url);
            var data = gamesSearch.apiCall();//How do i get response from api call here?=====
            console.log(data);//returns undefined================   /*===*/
        //will change these when above works=====================
        } else if (!searchType || searchType === "channels") {
            var defaultSearch = new TwitchApiCall(searchType, searchTerm, params, url);
            defaultSearch.apiCall();
            displaySearchResults(defaultSearch.response.channels);
        } else {
            var streamSearch = new TwitchApiCall(searchType, searchTerm, params, url);
            streamSearch.apiCall();
            displaySearchResults(streamSearch.response.streams);
        }
    });
}
function TwitchApiCall(searchType, searchTerm, params, url) {
    this.params = params;
    this.url = url;
    this.apiCall = function() {
        $.ajax({
            url: this.url,
            data: this.params,
/*===*/     success: function (response) {
                next = response._links.next;
                prev = response._links.prev;
                console.log(response);//returns the object i want==================
            }
        });        /*===*/
        $("#page-title").html("Twitch.tv/" + searchType + "/" + searchTerm);
        $("#sort-pop").addClass('active');
    };
}

Thanks in advance