数学.round在JavaScript中不起作用

Math.round doesn't work in JavaScript

本文关键字：不起作用 JavaScript round 数学      更新时间：2023-09-26

在函数

中添加这一行之前，代码工作正常
parseLocalFloatCnt: num = Math.round(num*1.2);

有人知道怎么解决这个问题吗?由于

<!DOCTYPE html>
<html>
<body>
<p>Write something in the text field to trigger a function.</p>
<input type="text" id="myInput" oninput="myFunction()">
<p id="demo"></p>
<script>
function myFunction() {
    var x = parseLocalFloatCnt(document.getElementById("myInput").value);
    document.getElementById("demo").innerHTML = "You wrote: " + x;
}
function parseLocalFloatCnt(num) {
    num = Math.round(num*1.2);
    return +(num.replace(getLocalDecimalSeparator(), '.'));
}
function getLocalDecimalSeparator() {
    var n = 1.1;
    return n.toLocaleString().substring(1,2);
}
</script>
</body>
</html>

Uncaught TypeError: num.replace is not a function(…)

你不能给replace打电话。

你可以这样做:

function parseLocalFloatCnt(num) {
    num = Math.round(num*1.2) + ''; // convert `num` to string
    return +(num.replace(getLocalDecimalSeparator(), '.'));
}

别忘了num to.String();

<!DOCTYPE html>
<html>
<body>
<p>Write something in the text field to trigger a function.</p>
<input type="text" id="myInput" oninput="myFunction()">
<p id="demo"></p>
<script>
    function myFunction() {
        var x = parseLocalFloatCnt(document.getElementById("myInput").value);
        document.getElementById("demo").innerHTML = "You wrote: " + x;
    }
    function parseLocalFloatCnt(num) {
        num = Math.round(num*1.2).toString();
        return +(num.replace(getLocalDecimalSeparator(), '.'));
    }
    function getLocalDecimalSeparator() {
        var n = 1.1;
        return n.toLocaleString().substring(1,2);
    }
</script>
</body>
</html>
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