写一个coffeescript函数，将json数组转换成我想要的格式，这是一种简洁的方式

What is a succinct way to write a coffeescript function that converts my json array into the format that I want

本文关键字：格式 一种 方式 简洁 我想要 数组 coffeescript 一个 函数 转换 json      更新时间：2023-09-26

我有这个json对象:

  op = [{"id":7,"d_set_id":1,"option_value_id":5,"product_id":3,"model":"1300","option_type":"Plunger Diameter","option":"5.0 inch Plunger Diameter","product":"Packing","route":"part_option_values","reqParams":null,"restangularized":true,"fromServer":true,"parentResource":{"route":"parts","parentResource":null,"id":"29"},"restangularCollection":false},{"id":9,"d_set_id":5,"option_value_id":11,"product_id":3,"model":"1300","option_type":"main drum diameter","option":"1.0  main drum diameter","product":"Packing","route":"part_option_values","reqParams":null,"restangularized":true,"fromServer":true,"parentResource":{"route":"parts","parentResource":null,"id":"29"},"restangularCollection":false}]

我写了这个函数来把它转换成我想要的格式:

addItems: (op) ->
   variant = { 
    product_id: "undefined"
    model: "undefined"
    options: []
    product: "undefinded"
    option_value_ids: []
    quantity: 1
  }   
  op.forEach (obj,i) ->
    variant.product_id = obj.product_id
    variant.model = obj.model
    variant.options.push obj.option
    variant.product = obj.product
    variant.option_value_ids.push obj.option_value_id
  variant.options = variant.options.join(', ')
  items.push variant

它成功地把它变成了我想要的结果。

  items = [{"product_id":3,"model":"1300","options":"5.0 inch Plunger Diameter, 1.0  main drum diameter","product":"Packing","option_value_ids":[5,11],"quantity":1},{"product_id":3,"model":"1300","options":"5.0 inch Plunger Diameter, 1.0  main drum diameter","product":"Packing","option_value_ids":[5,11],"quantity":1}]

…但这似乎不是一个非常简洁的方法来写这个函数。什么是更好的方法?

是的!这一切都可以用三个概念简洁地完成。映射、解构和对象简写表示法(ES2015/6和coffeescript中都有)

options = []
ids = []
# We need to aggregate id's and options first
for {option_value_id, option} in op
  ids.push option_value_id
  options.push option
# Map through to the new Object
items = op.map ({ product_id, model, product}) ->
  {
    product_id
    model
    options: options
    product
    option_value_ids: ids
    quantity: 1
  }

数组。map将接受一个数组并转换每个元素(在本例中是大对象的子集)并返回一个新的array。我们将在实参中解构传入的对象，然后将它们简化为对象格式。

数组映射对象Destructuring

速记符号

相关文章：