Javascript/jQuery运行太快——重载页面

Javascript/jQuery runs too fast - works on reloading page

本文关键字：重载 jQuery 运行 Javascript      更新时间：2023-09-26

我正在建立一个流动的网站。如果你在里面放一些图片，那简直就是地狱。IE或FF或Chrome有问题。

我又有问题了。基本上，我在运行时通过javascript构建网站。我首先要设置所有东西的宽度。之后，我设置主容器的高度。(否则图像会出现突发问题)。

现在我的问题是:如果我在本地执行网页，它在所有3个浏览器中都有效。如果我在线执行它，它不会设置主容器的高度(其中包含所有内容)。(var wrapperHeight = objLogo.offsetHeight;->返回0)

如果我刷新网页，一切看起来正常，上面一行返回有效的高度…我用一个简单的jquery脚本来翻转div(然而这是在我的简单脚本之后)。

注意:我还在正文上使用了一个相当大的背景图像，这是在css中设置的。第二个注意事项:它只发生在Chrome…

代码:

<head>
    <title></title>
    <link rel="stylesheet" href="css/default.css" type="text/css" />
    <script type="text/javascript" src="scripts/jquery-1.3.2.js"></script>
    <script type="text/javascript" src="scripts/jquery.quickflip.js"></script>
    <script type="text/javascript">
        $('document').ready(function(){
                            //getting inner width/height
            var windowWidth = window.innerWidth;
            var windowHeight = window.innerHeight;
                            //getting width for the main container
            var wrapperWidth = schermBreedte*0.641;
                            //getting width for left and right div in main container
            var totalWrapperWidth = wrapperWidth - 40;
            var widthLeft = totalWrapperWidth*0.345;
            var widthRight = totalWrapperWidth*0.655;
                            //getting elements
            var objOrange = document.getElementById('orange');
            var objGreen = document.getElementById('green');
            var objFliptabs = document.getElementById('flip-tabs');
            var objLeft = document.getElementById('left');
            var objRight = document.getElementById('right');
            var objContent = document.getElementById('content');
            var objLogo = document.getElementById('main_logo');
            var objV_line = document.getElementById('v_line');
                            //setting main container (objOrange & ObjGreen are 2 main containers used for the flip jquery script, they are actually placed above eachother (see jquery ref above and script beneath)
            objOrange.style.width = wrapperWidth + "px";
            objGreen.style.width = wrapperWidth + "px";
            objFliptabs.style.width = wrapperWidth + "px";
                            //setting the left & right div
            objLeft.style.width = widthLeft + "px";
            objRight.style.width = widthRight + "px";
                            //this logo is placed in the left div. The actual main container height is determined by getting the height of this logo after setting the width
            objLogo.style.width = (widthLeft-20)+"px";
                            //the right div is splitted into two pieces: a top which contains 6 images and a bottom which contains 1 image, the objectContent refers to the bottom as the top height is set dynamically by setting the width of the 6 images in %
            objContent.style.width = widthRight  + "px";
                            //getting the height for the main container by getting the height of the image (we've set the width of the image earlier - see above - so that it is scaled proportionally)
            var wrapperHeight =  objLogo.offsetHeight;
                            //setting the height of the main containers
            objOrange.style.height = wrapperHeight + "px";
            objGreen.style.height = wrapperHeight + "px";
                           //setting the height of a 1px line next to the left div
            objV_line.style.height = 100 + "%"
                            //getting the height of the content div (=2nd and bottom div of the right div)
            var contentHeight = wrapperHeight*0.445;
                            //setting the height
            objContent.style.height = contentHeight + "px";
                            //another line
            var length = parseInt(document.getElementsByTagName("div")["right"].offsetWidth) - 20;
            var line = document.getElementById('hor_lijn');
            line.style.width = lengte + "px";   
            $('#flip-container').quickFlip();
            $('#flip-navigation li a').each(function(){
                $(this).click(function(){
                    $('#flip-navigation li').each(function(){
                        $(this).removeClass('selected');
                    });
                    $(this).parent().addClass('selected');
                    var flipid=$(this).attr('id').substr(4);
                    $('#flip-container').quickFlipper({ }, flipid, 1);
                    return false;
                });
            });

        });
    </script>
</head>

看起来您需要等待运行代码，直到图像加载，以便他们的大小是已知的，因此可以正确计算高度

尝试使用这个jQuery插件:

https://github.com/desandro/imagesloaded 

$(document).ready(function() {
    $('#my-image-container').imagesLoaded(function() {
        /* your code here */
    });
});

当文档。Ready被触发时，浏览器并不需要在内存中存储图像来确定它们的高度/宽度。

一个选择是把你的大小调整逻辑放在$(window).ready()中而不是$(document).ready()中。两者之间的区别就是那扇窗。Ready将等待所有内容加载。

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