当数据不按顺序排列时，如何对数组中的json数据进行排序

var data = [
  {
    cid: "59eb15be",
    parentCid: "",
    lv: 1,
    number: "2",
    subject: "Title 2"
  },
  {
    cid: "d7d851ef",
    parentCid: "",
    lv: 1,
    number: "4",
    subject: "Title4"
  },    
  {
    cid: "bd01cc50",
    parentCid: "ae35e67d",
    lv: 2,
    number: "1.1",
    subject: "Title1.1"
  },
  {
    cid: "2d8bd8b0",
    parentCid: "",
    lv: 1,
    number: "3",
    subject: "Title3"
  },
  {
    cid: "7f66a92d",
    parentCid: "ae35e67d",
    lv: 2,
    number: "1.2",
    subject: "Title1.2"
  },
  {
    cid: "ae35e67d",
    parentCid: "",
    lv: 1,
    number: "1",
    subject: "Title1"
  },
  {
    cid: "e7c2dbcc",
    parentCid: "ae35e67d",
    lv: 2,
    number: "1.3",
    subject: "Title1.3"
  },
  {
    cid: "cc784c42",
    parentCid: "ae35e67d",
    lv: 2,
    number: "1.4",
    subject: "Title1.4"
  }
];
	var chapterListDiv = document.getElementById("listSummary");
	var store = document.createDocumentFragment(); //we use this to store temporary orphaned childs
	for(var i=0; i<data.length; i++){
		var node = document.createElement("div");
		node.className = "lv" + (data[i].level || data[i].lv);
        var content = document.createTextNode(data[i].number + "." + " " + data[i].subject);
        node.appendChild(content);		
		node.setAttribute("data-id", data[i].cid); //set a data-id attribute. We need it for the orphaned values.
		node.setAttribute("data-parent-id", data[i].parentCid); //set a data-parent-id attribute. We need it for the orphaned values.
		if (data[i].parentCid == "") //we have a root node
		{
			chapterListDiv.appendChild(node);
		}
		else
		{
			var parent = chapterListDiv.querySelector('div[data-id="'+data[i].parentCid+'"]'); //look for a node with the parent id.
			if (parent) //parent is found
			{
				parent.appendChild(node);
			}
			else
			{
				store.appendChild(node); //temp store the node.
			}
		}
	}
    //final check
    var storeChilds = store.querySelectorAll('div[data-parent-id]');
    if (storeChilds)
    {
        Array.prototype.map.call(storeChilds, function(element){
            var parent = document.querySelector('div[data-id="'+element.getAttribute("data-parent-id")+'"]') ||
                store.querySelector('div[data-id="'+element.getAttribute("data-parent-id")+'"]')
            parent.appendChild(element);
            
        });
    }

.lv1 {
    
}
.lv2{
    padding-left: 30px;    
}
.lv3{
    padding-left: 30px;    
}

<div id="listSummary"></div>

在json数据中，所有项都有一个"cid"，其中一些项有"parentCid"，这意味着它是它的子级。(

作为第二级结果

1.3. Title1.3
1.4. Title1.4
1.1. Title1.1
1.2. Title1.2

这不是顺序，因为"1.1"answers"1.2"在循环中访问时找不到其父节点，因为它们的父节点在后面。所以这就是为什么"1.3"answers"1.4"被首先附加(父节点在前面(。

有没有什么方法可以像下面这样正确地获得第二级的结果？

1.1. Title1.1
1.2. Title1.2
1.3. Title1.3
1.4. Title1.4