如果信息无效，则使用jquery、Ajax将数据提交到数据库
data submitted into database if the informations are invalid using jquery,Ajax
我是Jquery和ajax的新手。我想检查邮件id是否已经存在于数据库中。所以我使用Ajax来检查电子邮件是否存在。我在提交表单时检查这个条件，所以我使用onSubmit事件。当我输入提交按钮时，上述条件被检查，然后插入到数据库中。但如果条件失败，电子邮件也插入数据库。误差是多少?我找不到这个错误，请帮助我!我的HTML代码是:
<body>
<div class="container">
<div class="row">
<div class="col-md-3">
</div>
<div class="col-md-6">
<div class="inner">
<h3>Registration</h3>
<form class="form-horizontal" method="post" action = "" onSubmit=" return checkmail();">
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Firstname</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="inputEmail3" placeholder="Firstname" name="fname">
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Lastname</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="inputEmail3" placeholder="Lastname"name="lname">
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Email</label>
<div class="col-sm-9">
<input type="email" class="form-control" id="email" placeholder="Email" name="email" >
<span id="check"></span>
</div>
</div>
<div class="form-group">
<label for="inputPassword3" class="col-sm-3 control-label">Password</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="pass" placeholder="Password" name="pass" >
</div>
</div>
<div class="form-group">
<label for="inputPassword3" class="col-sm-3 control-label">re-Password</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="repass" placeholder="re-Password">
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Mobile no</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="mob" placeholder="Mobile no" name="phone">
</div>
<h6 id="aaa"></h6>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Address1</label>
<div class="col-sm-9">
<textarea class="form-control" id="inputEmail3" placeholder="Address1" name="addr1"></textarea>
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Address2</label>
<div class="col-sm-9">
<textarea class="form-control" id="inputEmail3" placeholder="Address2(optional)"name="addr2"></textarea>
</div>
</div>
<div class="form-group">
<label class="control-label col-sm-3" >Country</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="inputEmail3" placeholder="Country" name="country">
</div>
</div>
<div class="form-group">
<label class="control-label col-sm-3" >State</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="inputEmail3" placeholder="State" name="state">
</div>
</div>
<div class="form-group">
<label class="control-label col-sm-3" >City</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="inputEmail3" placeholder="City" name="city">
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Zipcode</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="zip" placeholder="EX:456322" name="zip" >
</div>
</div>
<div class="form-group">
<div class="col-sm-offset-2 col-sm-10">
<input type="submit" class="btn btn-default" name="submit" value="Register">
</div>
</div>
</form>
</div>
</div>
<div class="col-md-3">
</div>
</div>
</div>
我的Jquery函数是
function checkmail(){
var mail= $('#email').val();
if(mail ==""){
$("#email").focus();
alert("Enter mail id");
return false;
}
else
{
$.ajax({
type:'post',
url :'check.php',
data: {emailid:mail},
success: function(responseText){
$("#check").html(responseText);
if(responseText != 1) { // if the response is 1
$("#check").html("Available!");
return true;
}
else {
// else blank response
$("#email").focus();
$("#check").html("Email are already exist.");
return false;
}
}
});
}
}
</script>
check.php
<?php
$con = new mysqli('localhost','root','','registration'); //set coonection to db
$mail = $_POST['emailid'];
$query = mysqli_query($con, "select email from user where email='".$mail."' ");
if(mysqli_num_rows($query) > 0)
{
echo '1'; // if mail exist
}
?>
提前感谢。
你应该这样做:
<form class="form-horizontal" method="post" action = "" onSubmit="checkmail()">
并将脚本放在body标签开始后。
我建议你使用jquery
$("#form-id").on('submit',function(e){
e.preventDefault();
// Validation for data
});
使用下面的代码，只需做一些修改。
HTML
<body>
<div class="container">
<div class="row">
<div class="col-md-3">
</div>
<div class="col-md-6">
<div class="inner">
<h3>Registration</h3>
<form id="myForm" class="form-horizontal" method="post" action="">
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Firstname</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="inputEmail3" placeholder="Firstname" name="fname">
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Lastname</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="inputEmail3" placeholder="Lastname"name="lname">
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Email</label>
<div class="col-sm-9">
<input type="email" class="form-control" id="email" placeholder="Email" name="email" >
<span id="check"></span>
</div>
</div>
<div class="form-group">
<label for="inputPassword3" class="col-sm-3 control-label">Password</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="pass" placeholder="Password" name="pass" >
</div>
</div>
<div class="form-group">
<label for="inputPassword3" class="col-sm-3 control-label">re-Password</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="repass" placeholder="re-Password">
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Mobile no</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="mob" placeholder="Mobile no" name="phone">
</div>
<h6 id="aaa"></h6>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Address1</label>
<div class="col-sm-9">
<textarea class="form-control" id="inputEmail3" placeholder="Address1" name="addr1"></textarea>
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Address2</label>
<div class="col-sm-9">
<textarea class="form-control" id="inputEmail3" placeholder="Address2(optional)"name="addr2"></textarea>
</div>
</div>
<div class="form-group">
<label class="control-label col-sm-3" >Country</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="inputEmail3" placeholder="Country" name="country">
</div>
</div>
<div class="form-group">
<label class="control-label col-sm-3" >State</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="inputEmail3" placeholder="State" name="state">
</div>
</div>
<div class="form-group">
<label class="control-label col-sm-3" >City</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="inputEmail3" placeholder="City" name="city">
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Zipcode</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="zip" placeholder="EX:456322" name="zip" >
</div>
</div>
<div class="form-group">
<div class="col-sm-offset-2 col-sm-10">
<input type="button" onClick="checkmail();" class="btn btn-default" name="submit" value="Register">
</div>
</div>
</form>
</div>
</div>
<div class="col-md-3">
</div>
</div>
</div>
JQuery代码
function checkmail(){
var mail= $('#email').val();
if(mail ==""){
$("#email").focus();
alert("Enter mail id");
return false;
}
else
{
$.ajax({
type:'post',
url :'check.php',
data: {emailid:mail},
success: function(responseText){
$("#check").html(responseText);
if(responseText != 1) { // if the response is 1
$("#check").html("Available!");
$("#myForm").submit();
}
else {
// else blank response
$("#email").focus();
$("#check").html("Email are already exist.");
return false;
}
}
});
}
}
相应地更改form的id，保持为myForm
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