将php字符串回显为javascript函数的问题

Problem echoing php string as javascript function

本文关键字：javascript 函数 问题 php 字符串      更新时间：2023-09-26

我正在使用Jaipho从自定义Wordpress插件向移动图库显示图像。使用Jaipho图库的wordpress主题使用WP-mobile-detector插件显示。

我遇到的问题是，当我使用php收集照片的url以回显出要由javascript解析的函数时。我从Safari的元素检查器中获取生成的静态javascript代码，并将其粘贴到我的代码中，注释掉php，它在任何地方都可以工作。Safari for iOS似乎不喜欢php生成的javascript代码。

  • HTML 5
    • <DOCTYPE html>
    • <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/>
    • <meta name="viewport" content="width=device-width; initial-scale=1.0; maximum-scale=1.0; user-scalable=0;"/>
    • PHP . 5.2.6
  • Wordpress 3.2.1

工作时:

  • 用户代理在Safari上设置为iPhone

  • 静态代码取代php生成的代码

    $imageArray = $case->images_assc_array();  
$i = 0;  
foreach($imageArray['views'] as $view_name => $view_images) {  
   $before_img = $view_images['before'];  
   $after_img = $view_images['after'];  
   echo "dao.ReadImage($i,'".$before_img->medium_size()."','".$before_img->small_size()."','".ucfirst($view_name)." Before','".$case->description."');";  
   $i++;  
   echo "dao.ReadImage($i,'".$after_img->medium_size()."','".$after_img->small_size()."','".ucfirst($view_name)." After','".$case->description."');";  
   $i++;  
}

期望生成的输出示例:

    dao.ReadImage( 0,'/wp-content/uploads/rmgallery_images/medium/408/before-front.jpg','/wp-content/uploads/rmgallery_images/small/408/before-front.jpg','Front Before','38 year old who underwent a tummy tuck.');  
    dao.ReadImage( 1,'/wp-content/uploads/rmgallery_images/medium/410/after-front.jpg','/wp-content/uploads/rmgallery_images/small/410/after-front.jpg','Front After','38 year old who underwent a tummy tuck.');
    dao.ReadImage( 2,'/wp-content/uploads/rmgallery_images/medium/409/before-side.jpg','/wp-content/uploads/rmgallery_images/small/409/before-side.jpg','Side Before','38 year old who underwent a tummy tuck.');
    dao.ReadImage( 3,'/wp-content/uploads/rmgallery_images/medium/411/after-side.jpg','/wp-content/uploads/rmgallery_images/small/411/after-side.jpg','Side After','38 year old who underwent a tummy tuck.');

你有一些不匹配的引号:

echo dao.ReadImage($i,'".$before...

echo "dao.ReadImage($i,'".$after...

等等。

试试这些:

echo 'dao.ReadImage('.$i.',"'.$before_img->medium_size().'","'.$before_img->small_size().'","'.ucfirst($view_name).' Before","'.$case->description.'");';
echo 'dao.ReadImage('.$i.',"'.$after_img->medium_size().'","'.$after_img->small_size().'","'.ucfirst($view_name).' After","'.$case->description.'");';

感谢@Marc B和@linuxrules94的联合解决方案:

<?php
$imageArray = $case->images_assc_array();
$i = 0;
    foreach($imageArray['views'] as $view_name => $view_images):
        $before_img = $view_images['before'];
        $after_img = $view_images['after'];
    ?>
        dao.ReadImage(<?=json_encode($i);?>, <?=json_encode($before_img->medium_size());?>,<?=json_encode($before_img->small_size());?>,<?=json_encode(ucfirst($view_name));?> + " Before", <?=json_encode(stripslashes($case->description));?>);
        <? $i++; ?>
        dao.ReadImage(<?=json_encode($i);?>, <?=json_encode($after_img->medium_size());?>,<?=json_encode($after_img->small_size());?>,<?=json_encode(ucfirst($view_name));?> + " After", <?=json_encode(stripslashes($case->description));?>);
        <? $i++;
    endforeach; ?>

谢谢,大家好!

如何使用heredocs: http://php.net/manual/en/language.types.string.php

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